Given the roots of two binary trees p and q, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.
Example 1:
Input: p = [1,2,3], q = [1,2,3] Output: true
Example 2:
Input: p = [1,2], q = [1,null,2] Output: false
Example 3:
Input: p = [1,2,1], q = [1,1,2] Output: false
Constraints:
[0, 100].-104 <= Node.val <= 104/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
bool isSameTree(TreeNode* p, TreeNode* q) {
if(!p && !q)
return true;
else if(p && q)
return p->val==q->val && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
return false;
}
};