Given an m x n matrix of distinct numbers, return all lucky numbers in the matrix in any order.
A lucky number is an element of the matrix such that it is the minimum element in its row and maximum in its column.
Example 1:
Input: matrix = [[3,7,8],[9,11,13],[15,16,17]] Output: [15] Explanation: 15 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 2:
Input: matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]] Output: [12] Explanation: 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
Example 3:
Input: matrix = [[7,8],[1,2]] Output: [7] Explanation: 7 is the only lucky number since it is the minimum in its row and the maximum in its column.
Constraints:
m == mat.lengthn == mat[i].length1 <= n, m <= 501 <= matrix[i][j] <= 105.class Solution {
public List<Integer> luckyNumbers(int[][] matrix) {
int N = matrix.length, M = matrix[0].length;
int rMinMax = Integer.MIN_VALUE;
for (int i = 0; i < N; i++) {
int rMin = Integer.MAX_VALUE;
for (int j = 0; j < M; j++) {
rMin = Math.min(rMin, matrix[i][j]);
}
rMinMax = Math.max(rMinMax, rMin);
}
int cMaxMin = Integer.MAX_VALUE;
for (int i = 0; i < M; i++) {
int cMax = Integer.MIN_VALUE;
for (int j = 0; j < N; j++) {
cMax = Math.max(cMax, matrix[j][i]);
}
cMaxMin = Math.min(cMaxMin, cMax);
}
if (rMinMax == cMaxMin) {
return List.of(rMinMax);
}
return new ArrayList<>();
}
}