Find all valid combinations of k numbers that sum up to n such that the following conditions are true:
1 through 9 are used.Return a list of all possible valid combinations. The list must not contain the same combination twice, and the combinations may be returned in any order.
Example 1:
Input: k = 3, n = 7 Output: [[1,2,4]] Explanation: 1 + 2 + 4 = 7 There are no other valid combinations.
Example 2:
Input: k = 3, n = 9 Output: [[1,2,6],[1,3,5],[2,3,4]] Explanation: 1 + 2 + 6 = 9 1 + 3 + 5 = 9 2 + 3 + 4 = 9 There are no other valid combinations.
Example 3:
Input: k = 4, n = 1 Output: [] Explanation: There are no valid combinations. Using 4 different numbers in the range [1,9], the smallest sum we can get is 1+2+3+4 = 10 and since 10 > 1, there are no valid combination.
Constraints:
2 <= k <= 91 <= n <= 60class Solution {
List<List<Integer>> ans = new ArrayList<>();
public List<List<Integer>> combinationSum3(int k, int n) {
solve(k, n, new ArrayList<>(), 1);
return ans;
}
void solve(int k, int n, List<Integer> curr, int digit) {
if (curr.size() == k) {
if (n == 0)
ans.add(new ArrayList<>(curr));
return;
}
for (int i = digit; i < 10; i++) {
if (n - i < 0)
break;
curr.add(i);
solve(k, n - i, curr, i + 1);
curr.remove(curr.size() - 1);
}
}
}