You are given an array of k linked-lists lists, each linked-list is sorted in ascending order.
Merge all the linked-lists into one sorted linked-list and return it.
Example 1:
Input: lists = [[1,4,5],[1,3,4],[2,6]] Output: [1,1,2,3,4,4,5,6] Explanation: The linked-lists are: [ 1->4->5, 1->3->4, 2->6 ] merging them into one sorted list: 1->1->2->3->4->4->5->6
Example 2:
Input: lists = [] Output: []
Example 3:
Input: lists = [[]] Output: []
Constraints:
k == lists.length0 <= k <= 10^40 <= lists[i].length <= 500-10^4 <= lists[i][j] <= 10^4lists[i] is sorted in ascending order.lists[i].length won't exceed 10^4.class Solution {
public:
ListNode *mergeTwoLists(ListNode* l1, ListNode* l2) {
if (NULL == l1) return l2;
else if (NULL == l2) return l1;
if (l1->val <= l2->val) {
l1->next = mergeTwoLists(l1->next, l2);
return l1;
}
else {
l2->next = mergeTwoLists(l1, l2->next);
return l2;
}
}
ListNode *mergeKLists(vector<ListNode *> &lists) {
if (lists.empty()) return NULL;
int len = lists.size();
while (len > 1) {
for (int i = 0; i < len / 2; ++i) {
lists[i] = mergeTwoLists(lists[i], lists[len - 1 - i]);
}
len = (len + 1) / 2;
}
return lists.front();
}
};