You are given an integer array nums of size n.
Consider a non-empty subarray from nums that has the maximum possible bitwise AND.
k be the maximum value of the bitwise AND of any subarray of nums. Then, only subarrays with a bitwise AND equal to k should be considered.Return the length of the longest such subarray.
The bitwise AND of an array is the bitwise AND of all the numbers in it.
A subarray is a contiguous sequence of elements within an array.
Example 1:
Input: nums = [1,2,3,3,2,2] Output: 2 Explanation: The maximum possible bitwise AND of a subarray is 3. The longest subarray with that value is [3,3], so we return 2.
Example 2:
Input: nums = [1,2,3,4] Output: 1 Explanation: The maximum possible bitwise AND of a subarray is 4. The longest subarray with that value is [4], so we return 1.
Constraints:
1 <= nums.length <= 1051 <= nums[i] <= 106class Solution {
public int longestSubarray(int[] nums) {
int max = 0, count = 0, maxcount = 0;
for (int i = 0; i < nums.length; i++)
max = Math.max(max, nums[i]);
for (int i = 0; i < nums.length; i++) {
if (max == nums[i])
count++;
else {
maxcount = Math.max(maxcount, count);
count = 0;
}
}
maxcount = Math.max(maxcount, count);
return maxcount == 0 ? 1 : maxcount;
}
}