Given an array of integers nums and an integer k, return the total number of subarrays whose sum equals to k.
A subarray is a contiguous non-empty sequence of elements within an array.
Example 1:
Input: nums = [1,1,1], k = 2 Output: 2
Example 2:
Input: nums = [1,2,3], k = 3 Output: 2
Constraints:
1 <= nums.length <= 2 * 104-1000 <= nums[i] <= 1000-107 <= k <= 107class Solution {
public:
int subarraySum(vector<int>& nums, int k) {
unordered_map<int,int> mp;
int sum=0,ans=0;
mp[sum] = 1;
for(auto it:nums){
sum += it;
int find = sum - k;
if(mp.find(find) != mp.end()){
ans += mp[find];
}
mp[sum]++;
}
return ans;
}
};class Solution {
public:
int subarraySum(vector<int>& nums, int k) {
unordered_map<int,int> mp;
int sum=0,ans=0;
mp[sum] = 1;
for(auto it:nums){
sum += it;
int find = sum - k;
if(mp.find(find) != mp.end()){
ans += mp[find];
}
mp[sum]++;
}
return ans;
}
};class Solution {
public int subarraySum(int[] nums, int k) {
Map<Integer, Integer> prefixMap = new HashMap<>();
prefixMap.put(0, 1);
int n = nums.length, prefixSum = 0, ans = 0;
for (int i = 0; i < n; i++) {
prefixSum += nums[i];
ans += prefixMap.getOrDefault(prefixSum - k, 0);
prefixMap.put(prefixSum, prefixMap.getOrDefault(prefixSum, 0) + 1);
}
return ans;
}
}