Given a string expression representing an expression of fraction addition and subtraction, return the calculation result in string format.
The final result should be an irreducible fraction. If your final result is an integer, change it to the format of a fraction that has a denominator 1. So in this case, 2 should be converted to 2/1.
Example 1:
Input: expression = "-1/2+1/2" Output: "0/1"
Example 2:
Input: expression = "-1/2+1/2+1/3" Output: "1/3"
Example 3:
Input: expression = "1/3-1/2" Output: "-1/6"
Constraints:
'0' to '9', '/', '+' and '-'. So does the output.±numerator/denominator. If the first input fraction or the output is positive, then '+' will be omitted.[1, 10]. If the denominator is 1, it means this fraction is actually an integer in a fraction format defined above.[1, 10].class Solution {
public String fractionAddition(String expression) {
String[] operands = expression.split("/|(?=[+-])");
System.out.println(Arrays.toString(operands));
int num = 0, denom = 1;
for (int i = 0; i < operands.length; i += 2) {
int currNum = Integer.valueOf(operands[i]);
int currDenom = Integer.valueOf(operands[i + 1]);
num = num * currDenom + currNum * denom; // Cross-multiplication
denom = denom * currDenom;
}
// Convert to proper fraction by diving by HCF
int gcd = Math.abs(FindGCD(num, denom));
num /= gcd;
denom /= gcd;
return num + "/" + denom;
}
// Euclid's Algo
private int FindGCD(int a, int b) {
if (a == 0) return b;
return FindGCD(b % a, a);
}
}