There is a robot on an m x n grid. The robot is initially located at the top-left corner (i.e., grid[0][0]). The robot tries to move to the bottom-right corner (i.e., grid[m - 1][n - 1]). The robot can only move either down or right at any point in time.
Given the two integers m and n, return the number of possible unique paths that the robot can take to reach the bottom-right corner.
The test cases are generated so that the answer will be less than or equal to 2 * 109.
Example 1:
Input: m = 3, n = 7 Output: 28
Example 2:
Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Down -> Down 2. Down -> Down -> Right 3. Down -> Right -> Down
Constraints:
1 <= m, n <= 100class Solution {
public:
#define mp make_pair
map <pair<int, int>, int> memo;
int uniquePaths(int m, int n) {
if(!m || !n) return 0;
if (m==1 && n==1){
return 1;
}
if(!memo[mp(m-1, n)])
memo[mp(m-1, n)] = uniquePaths(m-1, n);
if(!memo[mp(m, n-1)])
memo[mp(m, n-1)] = uniquePaths(m, n-1);
return memo[mp(m-1, n)] + memo[mp(m, n-1)];
}
};