Given the root of a Binary Search Tree and a target number k, return true if there exist two elements in the BST such that their sum is equal to the given target.
Example 1:
Input: root = [5,3,6,2,4,null,7], k = 9 Output: true
Example 2:
Input: root = [5,3,6,2,4,null,7], k = 28 Output: false
Constraints:
[1, 104].-104 <= Node.val <= 104root is guaranteed to be a valid binary search tree.-105 <= k <= 105/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
unordered_map<int, int> m;
bool findTarget(TreeNode* root, int k) {
if(!root)
return false;
if(m[k-root->val])
return true;
m[root->val]++;
return (findTarget(root->left, k) || findTarget(root->right, k));
}
};