Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73] Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60] Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90] Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 10530 <= temperatures[i] <= 100class Solution {
public:
vector<int> dailyTemperatures(vector<int>& temperatures) {
stack <pair<int, int>> stk;
vector<int> res(temperatures.size(), 0);
for(int i=0; i<temperatures.size(); i++){
while(!stk.empty() && temperatures[i]>stk.top().first){
res[stk.top().second]=i-stk.top().second;
stk.pop();
}
stk.push({temperatures[i], i});
}
return res;
}
};